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HSC Year 11 Mathematics Extension 1 practice exams with worked answers
Study HSC Year 11 Mathematics Extension 1 with 5 topic note sets, 2 original practice exams and 5 topic tests with worked answers. These resources support school assessment. Preview a note section and worked question free.
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Further work with functions
Extension 1 asks you to build new graphs out of a graph you already know. The first and most important transformation is the reciprocal: given y = f(x), sketch y = 1/f(x). Rather than plotting points, you read features straight off the…
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Extension 1 asks you to build new graphs out of a graph you already know. The first and most important transformation is the reciprocal: given y = f(x), sketch y = 1/f(x). Rather than plotting points, you read features straight off the original curve.
- Zeros become vertical asymptotes. Wherever f(x) = 0, the reciprocal is undefined and its magnitude grows without bound, so draw a dashed vertical line there.
- Large values become small values. If f(x) → ±∞, then 1/f(x) → 0. In particular, if f(x) grows without bound as x → ±∞, the reciprocal has the horizontal asymptote y = 0. If f(x) → k (k ≠ 0), then 1/f(x) → 1/k.
- Sign is preserved. 1/f(x) is positive exactly where f(x) is positive, so the reciprocal stays on the same side of the x-axis.
- The values 1 and −1 are fixed. Where f(x) = ±1, the two graphs meet. These are useful anchor points.
- Turning points stay at the same x-value. A local maximum of f with a non-zero value becomes a local minimum of 1/f, and vice versa, because a larger positive number has a smaller reciprocal.
- Increasing becomes decreasing on any interval where f does not change sign.
Start with f(x) = x² − 4, a concave-up parabola with zeros at x = ±2 and minimum value −4 at x = 0.
Step 1: zeros x = ±2 become vertical asymptotes x = −2 and x = 2.
Step 2: as x → ±∞, f(x) → ∞, so 1/f(x) → 0⁺; the horizontal asymptote is y = 0, approached from above.
Step 3: the minimum (0, −4) of f becomes a local maximum (0, −1/4) of the reciprocal.
Step 4: signs. For |x| > 2, f > 0, so the outer branches lie above the x-axis. For −2 < x < 2, f < 0, so the middle branch is below the axis, an upside-down ‘cap’ peaking at (0, −1/4) and plunging to −∞ at each asymptote.
Domain: x ≠ ±2. Range: y ≤ −1/4 or y > 0.
Reciprocal trigonometric functions. The three reciprocal ratios are cosec x = 1/sin x, sec x = 1/cos x and cot x = 1/tan x = cos x / sin x. Apply the rules above to the familiar sine, cosine and tangent graphs.
- y = cosec x has vertical asymptotes where sin x = 0, that is x = nπ (or 180°n). It touches y = 1 at x = π/2 + 2nπ and y = −1 at x = 3π/2 + 2nπ. Range: y ≤ −1 or y ≥ 1. Period 2π.
- y = sec x has asymptotes where cos x = 0, that is x = π/2 + nπ. It has local minima of 1 at x = 2nπ and local maxima of −1 at x = π + 2nπ. Range: y ≤ −1 or y ≥ 1. Period 2π. It is an even function, like cosine.
- y = cot x has asymptotes at x = nπ, zeros at x = π/2 + nπ, is decreasing on each branch and has period π. Its range is all real numbers.
Domain: cos x ≠ 0, so x ≠ π/2, 3π/2 within [0, 2π]. Since sec x ≤ −1 or sec x ≥ 1, the range of 2 sec x is y ≤ −2 or y ≥ 2.
Solve: sec x = 2 means cos x = 1/2, so x = π/3 or x = 5π/3. Both lie in the domain.
When working in degrees the same shapes apply, with asymptotes at multiples of 90° or 180°. Always label asymptotes with dashed lines and mark the points where the reciprocal meets the original curve at y = ±1.
Let f(x) = x and g(x) = (x − 3)². For which values of x is the product y = f(x)g(x)…
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- x < 0 or x > 3
- 0 < x < 3
- x > 3
- x < 0
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Answer: D
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- Y11-FUN Further work with functions; Y11-POLY Polynomials; Y11-TRIG Further trigonometry; Y11-PERM Permutations and combinations; Y11-BIN The binomial theorem
- Y11-FUN Further work with functions; Y11-POLY Polynomials; Y11-TRIG Further trigonometry; Y11-PERM Permutations and combinations; Y11-BIN The binomial theorem
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- Further work with functions
- Polynomials
- Further trigonometry
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- Permutations and combinations
- The binomial theorem
Common questions about HSC Mathematics Extension 1
Is there a HSC Year 11 Mathematics Extension 1 practice exam with answers?
Yes. This Year 11 pack includes 2 original synoptic practice exams and 5 separate 20-mark topic tests, with worked solutions and marking guides. These are original practice materials, not official board examinations. Preview a sample note and worked question before buying.
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The HSC Year 11 Mathematics Extension 1 pack follows the versions listed on its Official curriculum sources page. 2027 applicability is verified against the recorded official evidence. Your school determines its assessment program and selected texts or topics. These are original study resources, not official board publications.
What is included in the HSC Year 11 Mathematics Extension 1 Mastery Pack?
Original practice exams with answer guides, worked questions, digital flashcards and revision notes for Mathematics Extension 1. A sample note section and worked question are available free. The curriculum sources page links the official course documents. Preview the sample note, worked question and contents here. Paid resources unlock with a one-time purchase from $20, with access while the platform operates.
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