← Full deck and preview

Free QCE Year 11 Specialist Mathematics Flashcard Review

Review 20 public cards with spaced repetition. Flip a card, then grade your recall. Cards you miss return today. Your schedule stays in this browser.

Loading your review schedule…

Browse the free cards

State the multiplication principle.

If one stage can be done in m ways and the next in n ways, together they can be done in m × n ways.

When do you use the addition principle?

When the alternatives are mutually exclusive (cannot both happen): add the counts.

Inclusion–exclusion for two sets?

|A ∪ B| = |A| + |B| − |A ∩ B|.

What is 0! and why?

0! = 1, so that formulas such as ⁿPₙ = n!/0! remain consistent.

Formula for ⁿPᵣ?

ⁿPᵣ = n!/(n − r)!, the number of ordered selections of r from n distinct objects.

Formula for ⁿCᵣ?

ⁿCᵣ = n!/(r!(n − r)!), the number of unordered selections.

Arrangements of n objects with p alike and q alike?

n!/(p! q!).

How do you count arrangements with certain objects together?

Treat them as one block, arrange the blocks, then multiply by the internal arrangements.

Why is ⁿCᵣ = ⁿCₙ₋ᵣ?

Choosing r to include is the same as choosing n − r to exclude.

How do you select from multiple groups?

Multiply the combinations for each group, e.g. ⁵C₂ × ⁷C₃.

Inclusion–exclusion for three sets?

|A ∪ B ∪ C| = |A| + |B| + |C| − |A ∩ B| − |A ∩ C| − |B ∩ C| + |A ∩ B ∩ C|.

Quick way to find P(at least one)?

1 − P(none).

When is the implication P ⇒ Q false?

Only when P is true and Q is false.

Converse of P ⇒ Q?

Q ⇒ P. It may or may not be true.

Contrapositive of P ⇒ Q?

¬Q ⇒ ¬P, which is logically equivalent to P ⇒ Q.

Negation of P ⇒ Q?

P and ¬Q.

What does P ⟺ Q mean and how is it proved?

P if and only if Q; prove both P ⇒ Q and Q ⇒ P.

Negation of ∀x, P(x)?

∃x such that ¬P(x).

Define ℚ and ℚ′.

ℚ: numbers a/b with a, b ∈ ℤ, b ≠ 0. ℚ′: real numbers that are not rational (irrationals).

Is 0 in ℤ⁺?

No. 0 ∈ ℤ, but 0 is in neither ℤ⁺ nor ℤ⁻.