Free VCE Specialist Mathematics Flashcard Review
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State the difference between a conjecture, a proof and a counter-example.
A conjecture is a statement proposed as true but not yet proved; a proof establishes it is true in all stated cases; a single counter-example disproves it. One counter-example refutes a universal claim, but no number of supporting examples proves one.
What does the implication P ⇒ Q mean, and what is its converse?
P ⇒ Q ('if P then Q') means whenever P is true, Q is true; P is sufficient for Q and Q is necessary for P. Its converse is Q ⇒ P, which is a logically different statement and need not be true.
Explain 'P if and only if Q' (P ⇔ Q) in terms of necessary and sufficient conditions.
P ⇔ Q means both P ⇒ Q and Q ⇒ P hold, so P and Q are logically equivalent. P is then both necessary and sufficient for Q; proving an iff requires proving both implications.
What is proof by cases (proof by exhaustion)?
Split the situation into a finite set of exhaustive, mutually relevant cases and prove the statement separately in each; if it holds in every case, it holds in general. Example: proving a property for all integers by treating even and odd separately.
Outline the logic of proof by contradiction.
Assume the statement is false (assume its negation), then derive a logical contradiction. Since the assumption leads to a contradiction, the original statement must be true. Classic example: proving √2 is irrational.
State the contrapositive of P ⇒ Q and why proving it works.
The contrapositive is ¬Q ⇒ ¬P ('if not Q then not P'). A statement and its contrapositive are logically equivalent, so proving the contrapositive proves the original implication.
What do the quantifiers '∀' and '∃' mean, and how is each disproved?
∀ means 'for all' (the claim holds for every element); ∃ means 'there exists' (at least one element satisfies it). A '∀' statement is disproved by one counter-example; a '∃' statement is disproved by showing no element works.
State the two steps of a proof by mathematical induction.
Base step: prove the statement P(n) is true for the first value (often n=1). Inductive step: assume P(k) is true (the inductive hypothesis) and use it to prove P(k+1). Together these show P(n) holds for all integers n ≥ the base value.
In induction, what exactly is the inductive hypothesis and how is it used?
The inductive hypothesis is the assumption that P(k) is true for an arbitrary k. It is used as a given within the inductive step to derive P(k+1); the proof must explicitly invoke it, otherwise the induction is invalid.
How is induction used to prove a divisibility result such as 'n3 − n is divisible by 6'?
Show the base case holds (n=1 gives 0, divisible by 6). Assume k3 − k = 6m, then expand (k+1)3 − (k+1) and rewrite it as (k3 − k) plus a multiple of 6, so it is divisible by 6, completing the induction.
What is a partial-fraction decomposition and when can a rational function be written as one?
It expresses a rational function P(x)/Q(x) (with deg P < deg Q) as a sum of simpler fractions whose denominators are the linear and irreducible quadratic factors of Q(x). If deg P ≥ deg Q, first divide to get a polynomial plus a proper rational part.
How do you find a vertical asymptote of a rational function?
A vertical asymptote occurs at x = a where the denominator is zero but the numerator is non-zero (after cancelling common factors). Near it the function magnitude → ∞; the graph approaches the line x = a without crossing it.
State the rule for the horizontal or oblique asymptote of a rational function based on degrees.
If deg(numerator) < deg(denominator): horizontal asymptote y = 0. If degrees are equal: horizontal asymptote y = ratio of leading coefficients. If numerator degree is exactly one more: an oblique (linear) asymptote found by polynomial division.
How is the second derivative used to classify a stationary point and identify concavity?
At a stationary point (f'(x)=0): if f''(x) > 0 it is a local minimum (curve concave up); if f''(x) < 0 it is a local maximum (concave down). If f''(x)=0 the test is inconclusive and other methods (e.g. sign of f') are needed.
Define a point of inflection and the condition for one.
A point of inflection is where the concavity of the curve changes (concave up to down or vice versa). It requires f''(x) = 0 (or undefined) at that point AND a sign change of f'' across it; f''=0 alone is not sufficient.
Write the Cartesian form of a complex number and its modulus.
A complex number is z = x + yi with x = Re(z), y = Im(z). Its modulus is |z| = √(x2 + y2), the distance from the origin to the point (x, y) in the Argand plane.
State the polar (modulus–argument) form of a complex number.
z = r cis θ = r(cos θ + i sin θ), where r = |z| ≥ 0 and θ = arg(z) is the angle from the positive real axis. The principal argument is usually taken in (−π, π].
How do modulus and argument behave under multiplication of complex numbers?
For z1z2: moduli multiply and arguments add, i.e. |z1z2| = |z1||z2| and arg(z1z2) = arg(z1) + arg(z2) (mod 2π). For division, moduli divide and arguments subtract.
State De Moivre's theorem.
For z = r cis θ and integer n, zn = rn cis(nθ) = rn(cos nθ + i sin nθ). It is used to compute powers and roots of complex numbers in polar form.
How are the nth roots of unity found and described geometrically?
The nth roots of unity are z = cis(2πk/n) for k = 0, 1, ..., n−1. They lie on the unit circle, equally spaced 2π/n apart, forming the vertices of a regular n-gon with one vertex at 1.