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Define equilibrium constant expression (Kc)

For a reaction aA + bB ⇌ cC + dD, Kc = [C]c[D]d / [A]a[B]b. Kc is the ratio of product concentrations to reactant concentrations at equilibrium, each raised to the power of their stoichiometric coefficients. Kc is constant at a given temperature only.

What does a large Kc value indicate?

A large Kc value (Kc >> 1) indicates that at equilibrium, the reaction has proceeded far to the right, with products significantly favoured over reactants. The equilibrium lies far towards the products.

What does a small Kc value indicate?

A small Kc value (Kc << 1) indicates that at equilibrium, only a small proportion of reactants have been converted to products. The equilibrium lies far towards the reactants.

State Le Chatelier's principle

If a system at equilibrium is disturbed (by a change in concentration, pressure, temperature, or volume), the system will shift to counteract that change and re-establish equilibrium.

How does an increase in concentration of a reactant affect equilibrium?

An increase in reactant concentration shifts equilibrium to the right (towards products) to consume the excess reactant and re-establish Kc. The system produces more products.

How does a decrease in pressure affect an equilibrium with gases?

A decrease in pressure shifts equilibrium towards the side with the greater number of gas moles. If the forward reaction increases the number of moles, equilibrium shifts right; if it decreases moles, equilibrium shifts left.

How does an increase in temperature affect an exothermic equilibrium?

An increase in temperature shifts an exothermic equilibrium to the left (towards reactants) because heat is a product. The system counteracts the addition of heat. Kc decreases.

Describe the Haber process and its equilibrium conditions

N2 + 3H2 ⇌ 2NH3. Industrial conditions use high pressure (150–300 atm), moderately high temperature (400–500°C), and an iron catalyst. High pressure favours products (fewer moles on right). Lower temperature favours products (exothermic) but slower reaction, so 450°C is a compromise for reasonable yield and rate.

Describe the Contact process and its equilibrium conditions

2SO2 + O2 ⇌ 2SO3. Industrial conditions use moderate pressure (1–2 atm), moderate temperature (400–500°C), and a vanadium(V) oxide catalyst. The reaction is exothermic; lower temperatures favour products but slow the reaction. About 99% conversion is achieved.

Define Brønsted–Lowry acid

A Brønsted–Lowry acid is a proton (H+) donor. It donates H+ ions in aqueous solution (e.g., HCl → H+ + Cl-).

Define Brønsted–Lowry base

A Brønsted–Lowry base is a proton (H+) acceptor. It accepts H+ ions in aqueous solution (e.g., NH3 + H+ → NH4+).

What is a conjugate acid–base pair?

A conjugate acid–base pair differs by one proton (H+). If HX is an acid, X- is its conjugate base. If NH3 is a base, NH4+ is its conjugate acid. They are related by: acid ⇌ base + H+.

State the ionic product of water (Kw) at 25°C

Kw = [H+][OH-] = 1.0 × 10-14 at 25°C. In pure water, [H+] = [OH-] = 1.0 × 10-7 M, making pure water neutral (pH = 7).

Define pH and pOH

pH = −log10[H+]. pOH = −log10[OH-]. pH + pOH = 14 at 25°C. A solution is acidic if pH < 7, neutral if pH = 7, and basic if pH > 7.

Define the acid dissociation constant (Ka)

For a weak acid HA, Ka = [H+][A-] / [HA]. Ka is a measure of the strength of a weak acid; the larger the Ka, the stronger the acid (more dissociation). Ka is constant at a given temperature.

Define the base dissociation constant (Kb)

For a weak base B, Kb = [BH+][OH-] / [B]. Kb is a measure of the strength of a weak base; the larger the Kb, the stronger the base (more dissociation). Kb is constant at a given temperature.

Relate Ka, Kb, and Kw for a conjugate pair

For a weak acid HA and its conjugate base A-: Ka × Kb = Kw = 1.0 × 10-14 at 25°C. This shows that the stronger the acid, the weaker its conjugate base.

What is a buffer solution?

A buffer is a solution that resists changes in pH when small amounts of acid or base are added. A typical buffer contains a weak acid and its conjugate base (or a weak base and its conjugate acid) in roughly equal amounts.

Explain the buffer mechanism

When H+ is added to an acetate buffer, the conjugate base (CH3COO-) reacts with it: H+ + CH3COO- → CH3COOH. When OH- is added, the weak acid (CH3COOH) reacts: OH- + CH3COOH → CH3COO- + H2O. This maintains pH.

State the Henderson–Hasselbalch equation

pH = pKa + log10([A-] / [HA]). This relates the pH of a buffer to the pKa of the weak acid and the ratio of conjugate base to weak acid. When [A-] = [HA], pH = pKa.