ATARMAxxing · WACE Year 11 Mathematics Methods revision notes

Counting and probability

Unit 1 · Topic 1.1: Counting and probability
1 · Topic 1.1: Counting and probability

What this note covers

  1. Unordered selections and Pascal’s triangle
  2. Events as sets and the probability scale
  3. Addition, conditioning and independence
  4. Investigating probability using evidence and technology

4 sections · 5 key terms & formulas · 4 common mistakes

Free sample

A combination is a selection from distinct objects in which order has no significance. A team containing Alex, Bo and Chen is the same team as Chen, Alex and Bo. Before calculating, identify the objects, the required number and whether roles distinguish the selected people. Choosing three team members uses combinations; choosing a captain, secretary and treasurer does not, because changing roles changes the outcome.

State this modelling decision explicitly rather than choosing a formula simply because the question contains the word choose.

Factorial notation records descending products: n! = n(n − 1)…1, with 0! = 1. The number of unordered selections of r objects from n distinct objects is written nCr or C(n,r), and equals n!/[r!(n − r)!]. The numerator counts arrangements, while division removes arrangements of the selected and unselected groups that do not change the selection. For small numbers, cancelling common factors before multiplying avoids unnecessary arithmetic.

A calculator combination command is useful for large inputs, but does not decide whether order matters.

Worked example. Eight different students volunteer for a three-person panel with identical responsibilities. Order does not matter, so the number of panels is C(8,3) = 8!/(3!5!) = (8 × 7 × 6)/(3 × 2 × 1) = 56. Selecting the five students left out determines exactly the same panel, so C(8,5) also equals 56. This provides an independent reasonableness check.

Pascal’s triangle begins with the row 1, numbered zero. Each new row starts and ends with 1; each internal entry is the sum of the two entries immediately above it. Rows one through four are 1,1; 1,2,1; 1,3,3,1; and 1,4,6,4,1. Row n contains C(n,r) as r runs from zero to n. To expand (x + y)ⁿ, choose y from r of the n factors and x from all remaining factors. Thus the term xⁿ⁻ʳyʳ has coefficient C(n,r).

Worked example. Row four gives (x + y)⁴ = x⁴ + 4x³y + 6x²y² + 4xy³ + y⁴. The coefficient 6 counts the selections of two factors contributing y. Putting x = y = 1 gives 16, matching the sum 1 + 4 + 6 + 4 + 1 and checking the expansion.

Common questions

What does the WACE Year 11 Mathematics Methods note "Counting and probability" cover?

This note has 4 sections on Counting and probability. It includes 5 key terms and formulas, plus 4 common mistakes. It covers 1, Topic 1.1: Counting and probability. The full section list is shown under “What this note covers”.

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